Re: Another limit problem

Re: Another limit problem

Quote:

Originally Posted by

**Plato** Consider

and

.

Now the closer

is to

, the closer

is to

.

But

Are you sure about that? If I was to approach 2, I'm sure my f(x) would approach 1.

I think the problem with the statement as given is that you need to approach L FROM BOTH SIDES as you make x approach x_0 FROM BOTH SIDES in order to have L be the limit of f(x) as x approaches x_0.

Re: Another limit problem

The idea is that you need to not only approach it, but it is also required that you get *arbitrarily* close to the limit. In the example stated above, in a manner of speaking, you are "getting closer to" 0 from both sides, but you never get closer than 1 unit away. So the limit is not 0.

Re: Another limit problem

Thanks everyone for the reply! It is much more clear to me now. :) This was a bit of a funny question, seems like a lawyer question and not math hehe.

Re: Another limit problem

Re: Another limit problem

Quote:

Originally Posted by

**Plato** Yes, I am quite sure of it. The minimum value of

is

so the closer

is to

the closer

is to

.

(Bow)

-Dan