Originally Posted by

**ffezz** hi guys

i need to find the equation of the tangent at a certain point in the curve

the point it (1,2)

the equation is y= $\displaystyle sqrt(x^2 + 3)$

now here is what i have so far.

m = $\displaystyle f(x) - f(a) / x-a$

m = $\displaystyle sqrt (x^2 + 3) - sqrt(1^2 + 3) / x-1$

from that point i get lost. im assuming i have to multiply by the conjugate but i think im screwing something up when i do that.

If someone could do that with the inbetween steps I would appreciate it.

Also, teach me how to put things under a square root in the math tags XD

thanks