i need to find the equation of the tangent at a certain point in the curve
the point it (1,2)
the equation is y=
now here is what i have so far.
from that point i get lost. im assuming i have to multiply by the conjugate but i think im screwing something up when i do that.
If someone could do that with the inbetween steps I would appreciate it.
Also, teach me how to put things under a square root in the math tags XD
dont answer llawll i was factoring out nonexistent termx XD
I learnt something tonight XD
but Im messing up on my conjugate multiplication I think. Im getting a slope of -1/2 but should be getting 1/2.
heres what I did.
which gives me
then i factored the top to (x-3)(x-1) and removed the factor of x-1 so im left with
I can put in my numbers from there on and get -2/4 which is -1/2