I need help with a math problem or else Ms. Vick will lower my grade.
How do I find the limit and determine the continuity of this equation?
lim x*e^(yz)
(x,y,z) -> (2,0,1)
Thanks.
I need help with a math problem or else Ms. Vick will lower my grade.
How do I find the limit and determine the continuity of this equation?
lim x*e^(yz)
(x,y,z) -> (2,0,1)
Thanks.
The first question to ask when you are doing a limit: "Is there anything to stop the variables from taking on those quantities?" In particular, things to look out for that can happen are $\displaystyle 0/0, \, \infty/ \infty, \, 0^0$ and practically anything else that isn't well defined.Originally Posted by me > jallison + brownie
In this case nothing bad is going on. e^(0*1) is pretty tame and there's nothing to stop x from being 2. So basically you can just plug in the values for x, y, and z.
I can't help you with continuity, because you haven't listed an equation!
-Dan