y= ((2x-5)^-1 ) * (x^(2)-5x)^6
this is what i have so far
dy/dx=
(2x-5)^-1 * 6(x^2-5x)^5 * (2x-5) * 2 +
(x^2-5x)^6 * -1(2x-5)^-2 * 2
cancel the (2x-5) in the first term right
so then i have
12(x^2-5x)^5- 2(x^2-5x)^6 * (2x-5)^-2
factor out 2(x^2-5x)^5
so i have
2(x^2-5x)^5 [ 6-(x^2-5x)*(2-5)^-2]
now i am confused how to simplify this
the chain rule says: ........we take the derivative of the inside function once. we don't take the derivative of the derivative of g(x) (that would be g''(x), and that's not in the formula). (the only time we may have to do that is if g(x) itself is a composite function, which was not the case here)