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Math Help - Integrate function

  1. #1
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    Question Integrate function

    hi
    how do i integrate the following (what is the general format etc):

    1/((3x+1)^2)
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  2. #2
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by taurus View Post
    hi
    how do i integrate the following (what is the general format etc):

    1/((3x+1)^2)
    \int \frac{dx}{(3x + 1)^2}

    Let u = 3x + 1 \implies du = 3dx, so
    \int \frac{dx}{(3x + 1)^2} = \frac{1}{3} \int \frac{du}{u^2}

    You can do it from there.

    -Dan
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  3. #3
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    Question

    does this seem right"

    => 1/2 (U^-1/-1)
    => -1/(2U)
    ?
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  4. #4
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by taurus View Post
    does this seem right"

    => 1/2 (U^-1/-1)
    => -1/(2U)
    ?
    it's 1/3 not 1/2
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  5. #5
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    ooop yea thanks
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  6. #6
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by taurus View Post
    ooop yea thanks
    and of course, you should remember to replace u with 3x + 1 when done
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