find y" of x+xy+y=2
so i did the first differncition as
1+y+x(dy/dx)+1(dy/dx) = 0
y= 1+y/x+1
y"= ?
somebody solve this for me ?
y" = ( 1+y)-(x+1)/ (x+1)^2
i think this is not right .
what is the answear. show me with working !
So you've already taken the first differentiation which is,
from the given equation we know that,
for later use, let's isolate from (1),
to find , differentiate the equation (2) w.r.t x,