$\displaystyle Lim\frac{\1}{x^2}=\frac{\1}{4}$

$\displaystyle x\rightarrow2$

So I start with :

$\displaystyle \frac{\1}{x^2}-\frac{\1}{4}$

which breaks down to :

$\displaystyle \frac{\(x-2)(x+2)}{4x^2}$

But I'm confused how to bound this to get a delta.

(PS: I cant figure out how to put the absolute value signs in here, but I know they are supposed to be there)

Do I break it down to :

$\displaystyle (x-2)*\frac{\(x+2)}{4x^2}=(x-2)*\frac{\1}{4x}+\frac{\1}{2x^2}$

Then what?