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Math Help - implicit differentiation

  1. #1
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    implicit differentiation

    dy/dx when -xy^2 + 10x^2y = -x + 2

    i got

    (10x^2 - 2yx + 10xy + 1) / y^2 = dy/dx

    can some one please check if this is right
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by helmszee View Post
    dy/dx when -xy^2 + 10x^2y = -x + 2

    i got

    (10x^2 - 2yx + 10xy + 1) / y^2 = dy/dx

    can some one please check if this is right
    that's not what i got, so i guess you're wrong
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  3. #3
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    ....wanna let me know wat u get or how u got it then plz
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  4. #4
    is up to his old tricks again! Jhevon's Avatar
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    ok, i'll post. see if you can spot a mistake, if any. i'm kind of tired and too lazy to check through it myself, it will be good practice for you

    -xy^2 + 10x^2 y = -x + 2

    differentiating implicitly we get

    -y^2 - 2xy~\frac {dy}{dx} + 20xy + 10x^2~\frac {dy}{dx} = -1

    \Rightarrow \frac {dy}{dx} \left( 10x^2 - 2xy \right) = y^2 - 20xy - 1

    \Rightarrow \frac {dy}{dx} = \frac {y^2 - 20xy - 1}{10x^2 - 2xy}

    everything good?
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