This question is in the Parametric Equations and Polar Coordinates section of Multivariable Calculus, 6th Edition by James Stewart. I have to find a Cartesian equation for the curve:
rcos(theta)=1
and then identify it. I find this section a little confusing.
Thanks for the help.
As another question, and this one I'm sure is a little trickier (not to mention I think I got the answer). When you have r = 2sin(theta) + 2cos(theta), you have to transform it into Cartesian coordinates and identify the curve. The first question I was thrown off because it asked for a curve so I didn't think a line would qualify.
Anyways in this second question I put cos(theta) = x/r and sin(theta) = y/r.
I then plugged these values in the equation and got r = 2x/r + 2y/r. I eliminated the r and got 2x + 2y = 1. This gave me the equation of a line y = -x + 1/2. And I think this is the answer. Tell me if I'm wrong.
well, excuse me for being lazy. but there have been times when i thought in simplifying stuff that i thought would be a circle, i ended up with an ellipse. i just wanted to be on the safe side.
...well, now that i think about it, i guess we're only in danger of that if the coefficients of x^2 and y^2 are not 1, but oh, well. let's just say i wanted the poster to verify it for me, you know, so he can practice his algebra (i'm so considerate). stop picking on me
i see what Krizalid is talking about now you're just a bully