If , then . Solve this equation for y'(x) and make sure you use parentheses where necessary.
Hello,in a textbook exercise,the solution to the function y(x)=x^y(x) is given with differential.We set Xo=1,therefore y(xo)=y(1)=1.Then dy=y'(xo)dx=>dy=y'(1)*(1.1-1).Then it uses implicit factoring, y'(1)=y^2(1)/1/1-y(1)ln1=1.How do we get from y(1)=x^y(x to y'(1)=y^2(1)/1/1-y(1)ln1.I'm obviously missing something in terms of factoring,can someone help me?PS:The exercise's main goal is to find y(1.1)