7x^9-4x^5+2x-13/ -3x^9+x^8-5x+2x
lim-- infinity
and these
2x^2+1/6+x-3x^2
lim ---- infinity
Am I correct in assuming that these are $\displaystyle \displaystyle \begin{align*} \lim_{x \to \infty}\frac{7x^9 - 4x^5 + 2x - 13}{-3x^2 + x^8 - 5x + 2x} \end{align*}$ and $\displaystyle \displaystyle \begin{align*} \lim_{x \to \infty}\frac{2x^2 + 1}{6+x-3x^2} \end{align*}$?
Next time please either learn some LaTeX or else at least use brackets where they're needed to make the expressions make sense.
Just to clarify, you mean $\displaystyle \displaystyle \begin{align*} \lim_{x \to \infty}\frac{7x^9 - 4x^5 + 2x - 13}{-3x^9 + x^8 - 5x + 2x} \end{align*}$
arsenal12345, divide both numerator and denominator by the highest power of x ($\displaystyle x^9$ in the first problem, $\displaystyle x^2$ in the second).