evaluate the following limits

**arsenal12345** · August 8th 2012, 11:28 PM

7x^9-4x^5+2x-13/ -3x^9+x^8-5x+2x

lim-- infinity

and these

2x^2+1/6+x-3x^2

lim ---- infinity

**emakarov** · August 9th 2012, 05:11 AM

Originally Posted by arsenal12345

7x^9-4x^5+2x-13/ -3x^9+x^8-5x+2x

lim-- infinity

Please confirm that the expression whose limit you need to find is exactly as written above.

**Prove It** · August 9th 2012, 05:54 AM

Originally Posted by arsenal12345

7x^9-4x^5+2x-13/ -3x^9+x^8-5x+2x

lim-- infinity

and these

2x^2+1/6+x-3x^2

lim ---- infinity

Am I correct in assuming that these are $\displaystyle \begin{align*} \lim_{x \to \infty}\frac{7x^9 - 4x^5 + 2x - 13}{-3x^2 + x^8 - 5x + 2x} \end{align*}$ and $\displaystyle \begin{align*} \lim_{x \to \infty}\frac{2x^2 + 1}{6+x-3x^2} \end{align*}$ ?

Next time please either learn some LaTeX or else at least use brackets where they're needed to make the expressions make sense.

**HallsofIvy** · August 9th 2012, 06:57 AM

Originally Posted by Prove It

Am I correct in assuming that these are $\displaystyle \begin{align*} \lim_{x \to \infty}\frac{7x^9 - 4x^5 + 2x - 13}{-3x^2 + x^8 - 5x + 2x} \end{align*}$ and $\displaystyle \begin{align*} \lim_{x \to \infty}\frac{2x^2 + 1}{6+x-3x^2} \end{align*}$ ?

Next time please either learn some LaTeX or else at least use brackets where they're needed to make the expressions make sense.

Just to clarify, you mean $\displaystyle \begin{align*} \lim_{x \to \infty}\frac{7x^9 - 4x^5 + 2x - 13}{-3x^9 + x^8 - 5x + 2x} \end{align*}$

arsenal12345, divide both numerator and denominator by the highest power of x ( $x^9$ in the first problem, $x^2$ in the second).

**Prove It** · August 9th 2012, 07:20 AM

Originally Posted by HallsofIvy

Just to clarify, you mean $\displaystyle \begin{align*} \lim_{x \to \infty}\frac{7x^9 - 4x^5 + 2x - 13}{-3x^9 + x^8 - 5x + 2x} \end{align*}$

arsenal12345, divide both numerator and denominator by the highest power of x ( $x^9$ in the first problem, $x^2$ in the second).

I don't see any difference...

**emakarov** · August 9th 2012, 07:25 AM

Originally Posted by Prove It

Am I correct in assuming that these are $\displaystyle \begin{align*} \lim_{x \to \infty}\frac{7x^9 - 4x^5 + 2x - 13}{-3x^2 + x^8 - 5x + 2x} \end{align*}$

In the denominator, it should say $-3x^9$ , not $-3x^2$ .

**Prove It** · August 9th 2012, 07:27 AM

Ah right, I think I must need glasses :P

*Awkwardly realises I'm already wearing glasses ><

**arsenal12345** · August 9th 2012, 12:25 PM

yes u have assumed currecct man , i will try next time ,

so how do i solve them ?

**emakarov** · August 9th 2012, 12:28 PM

Originally Posted by HallsofIvy

arsenal12345, divide both numerator and denominator by the highest power of x ( $x^9$ in the first problem, $x^2$ in the second).

.

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