The equation 3lnx=lb3x is solved by the sqaure root of 3. Thanks
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3ln(x) = ln(3x) ln(x^{3}) = ln(3x) x^{3} = 3x x^{3} - 3x = 0 x (x^{2} - 3) = 0 x = 0 or else x^{2} - 3 = 0
Edited...
Originally Posted by tom@ballooncalculus 3ln(x) = ln(3x) ln(x^{3}) = ln(3x) x^{3} = 3x x^{3} - 3x = 0 x (x^{2} - 3) = 0 x = 0 or else x^{2} - 3 = 0 Note that and are NOT acceptable solutions, because is only defined for .
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