Solution of the ODE, dy/dx = 2xy^2, for which y(0)=1? And what is x when y reaches infinity?
Last edited by tykim; Aug 6th 2012 at 01:01 AM.
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Originally Posted by tykim Solution of the ODE, dy/dx = 2xy^2, for which y(0)=1? And what is x when y reaches infinity? When , so So the solution is , and if .
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