if y= 3sin(2x+3) show that y"+4y=0 and if y= sinx + 2cosx show that y", + y""+y, +y =O can some1 explain to me how to do these and solve them k thnx
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What is y'',Can you explain?
Hi, srirahulan. To answer your question, y'' is the second derivative of the function we are considering - in this case y=3sin(2x+3).
Last edited by GJA; Aug 5th 2012 at 09:51 PM.
Hi, arsenal12345. What we need to do is compute the second derivative y'' of y=3sin(2x+3) first. Then add 4y to what we get and see if it does equal zero. Does this answer your question? Good luck!
man i dont get it i am as lost as a nube can get
What GJA is saying, find $\displaystyle y''$ given that $\displaystyle y = 3 \sin (2x + 3)$. Does $\displaystyle y'' + 4y$ always equal zero?
no
Are you sure?
no not sure, can u please solve it and explain to me how u got ur answear ?
Originally Posted by arsenal12345 if y= 3sin(2x+3) show that y"+4y=0 and if y= sinx + 2cosx show that y", + y""+y, +y =O can some1 explain to me how to do these and solve them k thnx For the first one: $\displaystyle y'=6\cos(2x+3) $ $\displaystyle y'' = -12\sin(2x+3)$ Therefore... $\displaystyle LHS=y''+4y=-12\sin(2x+3)+4(3sin(2x+3))=0=RHS$ Do the same for the second one
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