Here I am able to evaluate the integral and arrive at the result:
However, I'm slightly concerned that I'm getting a function of
as a result rather than a numerical result... is this correct?
Either I'm correct and I'm over-thinking it, or it is an erroneous question (any double integrals I've seen in the past have the variable limits on the inner integral and the numerical limits on the outer integral, hence giving a numerical result), OR there is another way to deal with double integrals with variable limits on the outer integral that I'm not yet aware of. Which is it?