A positive number e and the limit L of a function f at -infinity are given. Find a negative number N such that ABS(f(x) -L) <e if x<N lim x approaches - infinty of 1/(x+19) =0 e= .008 N=?
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Originally Posted by zalar81957 A positive number e and the limit L of a function f at -infinity are given. Find a negative number N such that ABS(f(x) -L) <e if x<N lim x approaches - infinty of 1/(x+19) =0 e= .008 N=? I can barely understand your question. Are you asking to prove ? If so, you need to show that for some . So we can choose and reversing each step will prove
Last edited by Prove It; Aug 1st 2012 at 07:14 AM.
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