A positive number e and the limit L of a function f at -infinity are given. Find a negative number N such that ABS(f(x) -L) <e if x<N

lim

x approaches - infinty of 1/(x+19) =0

e= .008

N=?

Printable View

- August 1st 2012, 07:58 AMzalar81957finding negative number N so that f(x) - L <e
A positive number e and the limit L of a function f at -infinity are given. Find a negative number N such that ABS(f(x) -L) <e if x<N

lim

x approaches - infinty of 1/(x+19) =0

e= .008

N=? - August 1st 2012, 08:10 AMProve ItRe: finding negative number N so that f(x) - L <e