Let y = x + 1/x. Consider and express through y. Then express through and thus through y.
you mean to say that i am going to substitute the numerator first quantity by y and so it is y^3 then the second quantity would be solely y?
then the denominator as well? pls guide me on this sir so confused to find what does maximum value
i made the hint given by richard1234 (x^3 + 1/x^3) ^2
and so i have obtained this
f(x)= (y^3 + y^3 - 3y) / (y^6 - (y^3 - 3y)^2 - 2 - 2)
= (y^3 + y^3 - 3y) / (y^6 - ( y^6 + 6y^4 + 9y^2) - 4
= (y^3 + y^3 - 3y) / 6 y^4 - 9y^2 - 4
= y(2y^2 - 3) / 3y^2 ( 2y^2 - 3) - 4
im stuck here ...
need your help
Excellent post.I want to thank you for this informative read, I really appreciate sharing this great post. Keep up your work.This looks absolutely perfect.
best marriage site
All these tinny details are made with lot of background knowledge. I like it a lot. This was a useful post and I think it is rather easy to see from the other comments as well that this post is well written and useful.Aw, this was a really quality post. In theory I’d like to write like this too – taking time and real effort to make a good article… but what can I say…
khabar naak
I procrastinate a lot and never seem to get something done….