$\displaystyle \int\frac{1}{9.81+0.001v^2} dv$
I've actually forgotten how to do this. Any help please?
Edit: Actually, I'm not even sure if this is the correct forum or not, sorry.
$\displaystyle \int\frac{1}{9.81+0.001v^2} dv$
I've actually forgotten how to do this. Any help please?
Edit: Actually, I'm not even sure if this is the correct forum or not, sorry.
That is an arctangent form. See this page.
You can rewrite as $\displaystyle \frac{1}{10^{-3}}\frac{1}{9810+v^2}$