So Determine the domain of this fuction
y=√x^2-16
so first i factorised and get (x+4) and (x-4)
i m sure the domain has to be between -4 <x<4
what i am confused about is what happens to the square root , can some 1 how me how to do the proper workout for this problem ?
cheers
You were told that in Prove It's first response to your post: the quantity inside the square root must be non-negative and that happens for and .
I don't know what you mean by "work out y". If you mean just calculate y, for a given x, do exactly what the formula says: square x, subtract 16, then take the square root. If you mean that you want to find the range of the function, the set of all possible values of y, then you can note that a square root is never negative but, since can be any positive number and can be 0, the range is the set of all non-negative numbers.