I want to know if sigma[sin(1/n^2)] converges... Help!
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Yes, since $\displaystyle \left|\sin\left(\frac 1{n^2}\right)\leq \frac 1{n^2}$ and the series $\displaystyle \sum_{n\geq 1}\frac 1{n^2}$ is convergent.
I think got it! thanks for answering ^^
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