convergency test of ((2n+1)^n)/(n^(2n))

**shaharg** · July 21st 2012, 04:49 PM

Hy,
It's suppose to be simple one, but I really dont know how to start and what test should I apply.
((2n+1)^n)/(n^(2n))

Should I work on ((2n+1)/(n^2))^n?

**skeeter** · July 21st 2012, 07:01 PM

ratio and nth root tests

scroll down to the nth root test section + examples

**shaharg** · July 22nd 2012, 07:38 AM

Thanx

**Prove It** · July 22nd 2012, 07:49 AM

The ratio test also works.

**shaharg** · July 22nd 2012, 08:00 AM

Originally Posted by Prove It

The ratio test also works.

I have tried the ratio test, but putting n+1 instead of every n made it so complicated and stuff didn't cancel to me, I probably do it wrong.

**Plato** · July 22nd 2012, 08:42 AM

Originally Posted by shaharg

I have tried the ratio test, but putting n+1 instead of every n made it so complicated and stuff didn't cancel to me, I probably do it wrong.

The root test is really simple.
$\sqrt[n]{{\frac{{{{\left( {2n + 1} \right)}^n}}}{{{n^{2n}}}}}} = \frac{{2n + 1}}{{{n^2}}} \to 0$

**shaharg** · July 22nd 2012, 08:46 AM

Originally Posted by Plato

The root test is really simple.
$\sqrt[n]{{\frac{{{{\left( {2n + 1} \right)}^n}}}{{{n^{2n}}}}}} = \frac{{2n + 1}}{{{n^2}}} \to 0$

Yes it is simple.
I appreciate your effort. Thanx a lot.

Thread: convergency test of ((2n+1)^n)/(n^(2n))

LinkBack

Thread Tools

Display

convergency test of ((2n+1)^n)/(n^(2n))

Re: convergency test of ((2n+1)^n)/(n^(2n))

Re: convergency test of ((2n+1)^n)/(n^(2n))

Re: convergency test of ((2n+1)^n)/(n^(2n))

Re: convergency test of ((2n+1)^n)/(n^(2n))

Re: convergency test of ((2n+1)^n)/(n^(2n))

Re: convergency test of ((2n+1)^n)/(n^(2n))

Similar Math Help Forum Discussions

series convergency

Given a positive test result, find the probability that test taker has the disease.

Lost on Practice Test, teacher gave us test without answers to probems

Help testing these series with any root test or ratio test.

ratio test (series) urgent test tommorow!

Search Tags