Results 1 to 2 of 2

Math Help - Asymphtotes

  1. #1
    madalex
    Guest

    Asymphtotes

    I have to find out if the asymptotes of the following asymphtotes exist or not. And if they do exist I have to find out which type and the equation.

    f(x) = (x^2-4)(x+3) / x^2-1


    x =/ (cannot be) -1,1

    --------------------

    f(x) = 3x^2+4x-2 / x^2-9


    x =/ (cannot be) +- 3

    Hope I can get some help Im really strugling here..
    Follow Math Help Forum on Facebook and Google+

  2. #2
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Quote Originally Posted by madalex View Post
    I have to find out if the asymptotes of the following asymphtotes exist or not. And if they do exist I have to find out which type and the equation.

    f(x) = (x^2-4)(x+3) / x^2-1


    x =/ (cannot be) -1,1
    evidently you know what you are doing, but you did not answer the question. they want you to find the asymptotes and give their equations. you have not done that.

    the vertical asymptotes are: x = 1 and x = -1 ----> these are vertical lines

    what about horizontal asymptotes?

    to find horizontal asymptotes, you must find \lim_{x \to \infty}f(x) and \lim_{x \to - \infty}f(x). if either of those are finite numbers, then that (or those) are your horizontal asymptotes.

    example, if you realize that: \lim_{x \to \infty}f(x) = c, where c is a constant; and \lim_{x \to - \infty}f(x) = \infty. then y = c is your horizontal asymptote


    f(x) = 3x^2+4x-2 / x^2-9


    x =/ (cannot be) +- 3

    Hope I can get some help Im really strugling here..
    this is similar to the first question
    Follow Math Help Forum on Facebook and Google+

Search Tags


/mathhelpforum @mathhelpforum