The question is "Use implicit differentiation to write the equation of the tangent line to the graph at the specified point"
I'm given (x^2) - (2xy) + (y^2) - (2x) - (2y) + 1 = 0 with (2,3+2sqrt(2))
I tried to differentiate by the way I know getting 2x - (2xy' + 2y) + 2yy' - 2 - 2y' = 0 which simplies to (x-y-1)/(x-y+1) = y'
So I'm stuck here, is this it? am I done with the problem? I don't know why they gave me (2,3+2sqrt(2))
Can anyone help me please... I'm stuck..