x/(x+1) i let u=x+1 so x=u-1 i get answer of x+1-ln x +c book has answer of x - ln x +c what happened to the 1????
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Originally Posted by sluggerbroth x/(x+1) i let u=x+1 so x=u-1 i get answer of x+1-ln x +c book has answer of x - ln x +c what happened to the 1???? Both are correct. Notice that 1 + constant is still a constant. I am not sure how you could get x + 1 - ln|x| + C though...
Hint: $\displaystyle \frac{x}{x+1} = 1 - \frac{1}{x+1}$.
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