y=2-0.5x, y=0, x=1, x=2, rotate about the x axis.
I know that it will be easier to solve it with the regular method, but I need it with cylindrical shell.
I cannot find the radius and the height.
The final answer is 19pi/12
Thanx
y=2-0.5x, y=0, x=1, x=2, rotate about the x axis.
I know that it will be easier to solve it with the regular method, but I need it with cylindrical shell.
I cannot find the radius and the height.
The final answer is 19pi/12
Thanx
I suggest drawing a picture. The average radius of each shell is the distance from the axis of rotation to each given -value. Since the axis of rotation is simply the -axis, this distance is given by The "height" of each shell (horizontal distance from side to side) I have explained in my previous post. It should be clear from looking at a picture.