Hi everyone,

Could someone tell me if this is correct so far, please?

Integral 0 to 1 lnx/sq. x

lim t goes to 1 from the left lnx/sq. x

u=lnx

dv=sq. x

du=1/x

v=1/2xto the -1/2

lim t goes to 1 from the left lnx(1/2x^-1/2)-int.(1/2x^-1/2)(1/x)

Could I break this up into two integrals?

-1/2int. x^-1/2-1/2int. 1/x

Thank you very much