Hi everyone,
Could someone tell me if this is correct so far, please?
Integral 0 to 1 lnx/sq. x
lim t goes to 1 from the left lnx/sq. x
u=lnx
dv=sq. x
du=1/x
v=1/2xto the -1/2
lim t goes to 1 from the left lnx(1/2x^-1/2)-int.(1/2x^-1/2)(1/x)
Could I break this up into two integrals?
-1/2int. x^-1/2-1/2int. 1/x
Thank you very much