Another seemingly simple integral I am going blank on:

$\displaystyle \int \frac{1}{cosx-1}\,dx$

I really appreciate any help! I have tried different things but none of them seem to work.

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- Jun 25th 2012, 04:19 PMRagnarokIntegral with trig function in denominator
Another seemingly simple integral I am going blank on:

$\displaystyle \int \frac{1}{cosx-1}\,dx$

I really appreciate any help! I have tried different things but none of them seem to work. - Jun 25th 2012, 04:34 PMReckonerRe: Integral with trig function in denominator
$\displaystyle \int\frac1{\cos x - 1}\,dx$

$\displaystyle =\int\left(\frac1{\cos x - 1}\cdot\frac{\cos x + 1}{\cos x + 1}\right)\,dx$

$\displaystyle =\int\frac{\cos x + 1}{\cos^2x - 1}\,dx$

Check the spoiler if you're still stuck:

__Spoiler__: - Jun 25th 2012, 05:37 PMRagnarokRe: Integral with trig function in denominator
Thank you! I actually got that far but stopped because I thought I wasn't getting anywhere. How does the rest of the solution go?

- Jun 25th 2012, 05:42 PMReckonerRe: Integral with trig function in denominator
- Jun 28th 2012, 02:56 PMRagnarokRe: Integral with trig function in denominator
Thank you! I see it now.