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Math Help - Arc Length Problem, check my answer?

  1. #1
    Newbie andvaka's Avatar
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    [SOLVED] Arc Length Problem, check my answer?

    Mind checking my solution anyone? I worry that I may have left out a step because the given coordinates include both x and y values.
    Last edited by andvaka; June 24th 2012 at 11:16 PM.
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  2. #2
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    Re: Arc Length Problem, check my answer?

    Where is your solution? And your question, for that matter?
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  3. #3
    Newbie andvaka's Avatar
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    Re: Arc Length Problem, check my answer?

    My bad! Both are in the attachment.
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  4. #4
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    Re: Arc Length Problem, check my answer?

    Your derivative is incorrect. If \displaystyle \begin{align*} y = \frac{x^4 + 3}{6x} \end{align*}, this simplifies to \displaystyle \begin{align*} y = \frac{1}{6}x^3 + \frac{1}{2}x^{-1} \end{align*}, not \displaystyle \begin{align*} \frac{1}{6x^3} + \frac{1}{2}x^{-1} \end{align*}...
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  5. #5
    Newbie andvaka's Avatar
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    Re: Arc Length Problem, check my answer?

    That aside, did I use the relationship properly when I just plugged in the x values from the coordinates provided for the definite integral?
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  6. #6
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    Re: Arc Length Problem, check my answer?

    Your logic seems correct. Now you need to fix the mistake, solve the integral and evaluate the price.
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