Originally Posted by

**tleaf555** I'm just saying if you can graph the surfaces on a computer you can probably calculate volume too. In any case, these are the problems.

1.Volume bounded by x=0, x + y + z = 10 , z=0 and z = 4-(y2). I set up the integral as (-2,2) (0,4-(y2) ) (0,10-y-z) dx dz dy. My volume was 24.

2.Volume bounded by y = z2, y=16, x+y+z=3, x+y+z=30. I got (-4,4) (z^2 ,16) (3-y-z,30-y-z) dx dy dz. My volume was 2304

3.Volume bounded by z = x2 + y2, z=-4, x+y=1, x=0, y=0. I got (0,1) (0,1-y) (-4, x2 + y2 ) dz dx dy. My volume was 13/6.