Finding the area under a curve using integration of trig functions.

Hello!!

I had an integration exam today and I'm desperate to know if I answered this question correctly. As follows....

Find the area under the curve when Y= 5xsin(2x) when x=0, x=PI/2

I got 452, which I'm 99% sure is wrong but you never know!!

Thanks for your help and time in advance.

Chris. x

Re: Finding the area under a curve using integration of trig functions.

Re: Finding the area under a curve using integration of trig functions.

Re: Finding the area under a curve using integration of trig functions.

Quote:

Originally Posted by

**Purn** Hello!!

I had an integration exam today and I'm desperate to know if I answered this question correctly. As follows....

Find the area under the curve when Y= 5xsin(2x) when x=0, x=PI/2

I got 452, which I'm 99% sure is wrong but you never know!!

Thanks for your help and time in advance.

Chris. x

You might, by the way, have notice that since sine is never larger than 1, "5x sin(x/2)", between x= 0 and , cannot be larger than and so its integral cannot be larger than which is about 12.33. I can't imagine how you got "452"!