Hi! I'm struggling with this problem
Find an equation of the tangent line to the curve at the point (1, 8).
I am stuck because while I'm solving this, I keep getting 0/0.
How would you solve this problem?
Thanks!
Hi! I'm struggling with this problem
Find an equation of the tangent line to the curve at the point (1, 8).
I am stuck because while I'm solving this, I keep getting 0/0.
How would you solve this problem?
Thanks!
Rewrite as $\displaystyle y = 8x^{-\frac{1}{2}}$.
$\displaystyle \frac{dy}{dx} = -4x^{-\frac{3}{2}}$. At the point (1,8), $\displaystyle \frac{dy}{dx} = -4$.
Write the equation of the tangent line in point-slope form: $\displaystyle y - 8 = -4(x-1)$.