Finding the eq. of tangent line to this curve..

**kwonypoo** · June 17th 2012, 06:47 PM

Hi! I'm struggling with this problem
Find an equation of the tangent line to the curve

at the point (1, 8).
I am stuck because while I'm solving this, I keep getting 0/0.
How would you solve this problem?
Thanks!

**Cbarker1** · June 17th 2012, 07:04 PM

1. Find the differentiated function.
2. put in the (x,y) in the f'(x).
3. write the slope-pt form.

**richard1234** · June 17th 2012, 07:06 PM

Rewrite as $y = 8x^{-\frac{1}{2}}$ .

$\frac{dy}{dx} = -4x^{-\frac{3}{2}}$ . At the point (1,8), $\frac{dy}{dx} = -4$ .

Write the equation of the tangent line in point-slope form: $y - 8 = -4(x-1)$ .

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