If you are unsure how to use LaTeX, just use a / for the vinculum and use brackets where they are necessary. Otherwise inside tex tags, use the command \frac{}{}, with the numerator in the first set of brackets and the denominator in the second.
well for te first differential i got
3x^{2} + 3y^{2}(dy/dx)=0
dy/dx = (-x^{2} )/(y^{2})
Then seoncd differntial using quotient rule
[(y^{2})(-2x)-(-x^{2} )(2y(dy/dx))]/(y^{4})
then finally the second differntial came down to for me
[-2xy^{3} + 2x^{4} ]/y^{5}
Please help