Please someone please find the second differential for this equation

(x^{3}) + (y^{3}) = 1

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- Jun 17th 2012, 05:57 PMrighteous818Urgent second differential problem
Please someone please find the second differential for this equation

(x^{3}) + (y^{3}) = 1 - Jun 17th 2012, 06:03 PMProve ItRe: Urgent second differential problem
- Jun 17th 2012, 06:06 PMrighteous818Re: Urgent second differential problem
i did but i am not the gettin the answer the book said the answer is -2x/(y

^{5}) - Jun 17th 2012, 06:07 PMProve ItRe: Urgent second differential problem
- Jun 17th 2012, 06:07 PMrighteous818Re: Urgent second differential problem
how do i get fractions

- Jun 17th 2012, 06:11 PMProve ItRe: Urgent second differential problem
If you are unsure how to use LaTeX, just use a / for the vinculum and use brackets where they are necessary. Otherwise inside tex tags, use the command \frac{}{}, with the numerator in the first set of brackets and the denominator in the second.

- Jun 17th 2012, 06:15 PMrighteous818Re: Urgent second differential problem
well for te first differential i got

3x^{2}+ 3y^{2}(dy/dx)=0

dy/dx = (-x^{2})/(y^{2})

Then seoncd differntial using quotient rule

[(y^{2})(-2x)-(-x^{2})(2y(dy/dx))]/(y^{4})

then finally the second differntial came down to for me

[-2xy^{3}+ 2x^{4}]/y^{5}

Please help - Jun 17th 2012, 06:27 PMProve ItRe: Urgent second differential problem
- Jun 17th 2012, 06:31 PMrighteous818Re: Urgent second differential problem
thanks