hi, the question asks for the domain of f(x,y,z)=ln(z-x^2-y^2+2y+3). which is z-x^2-y^2+2y+3 > 0. when I try do describe the domain, all I get is 2 > x^2 + (y-1)^2 -z. I have no idea what the shape is like. any ideas? thx.
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Originally Posted by sjjc1993 hi, the question asks for the domain of f(x,y,z)=ln(z-x^2-y^2+2y+3). which is z-x^2-y^2+2y+3 > 0. when I try do describe the domain, all I get is 2 > x^2 + (y-1)^2 -z. I have no idea what the shape is like. Consider the surface By completing the square, we have This is a circular paraboloid, centered at (0,1,-4). So would consist of all the points above the paraboloid.
thanks a lot!
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