Thread: Maximum and minimum value

Show that the function f(x) = 1/squareroot(x) has neither the maximum value or the minimum value on (1,2).

maximum: lim f(x) as x-> 0 = infinity which is not in (1,2).
minimum: lim f(x) as x-> infinity = 0 which is not in (1,2).

Is this correct?

Originally Posted by tbyou87

Show that the function f(x) = 1/squareroot(x) has neither the maximum value or the minimum value on (1,2).

maximum: lim f(x) as x-> 0 = infinity which is not in (1,2).
minimum: lim f(x) as x-> infinity = 0 which is not in (1,2).

Is this correct?

i doubt it. i believe they are talking about the local max and min, as in, where the slope is zero, as in, find the derivative and show that it is never zero, particularly not in that interval