Show that the function f(x) = 1/squareroot(x) has neither the maximum value or the minimum value on (1,2).

maximum: lim f(x) as x-> 0 = infinity which is not in (1,2).

minimum: lim f(x) as x-> infinity = 0 which is not in (1,2).

Is this correct?

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- Oct 4th 2007, 05:27 PMtbyou87Maximum and minimum value
Show that the function f(x) = 1/squareroot(x) has neither the maximum value or the minimum value on (1,2).

maximum: lim f(x) as x-> 0 = infinity which is not in (1,2).

minimum: lim f(x) as x-> infinity = 0 which is not in (1,2).

Is this correct? - Oct 4th 2007, 10:06 PMJhevon