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Thread: hard definite integral

  1. June 14th 2012, 01:04 AM #1
    jacks
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    hard definite integral

    \displaystyle \int_{0}^{1}\frac{\sqrt{1-x^2}}{1-x^2\sin^2 x}dx
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  2. June 14th 2012, 03:14 PM #2
    simamura
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    Re: hard definite integral

    This integral can't be found in terms of elementary functions. Use Numerical Integration.
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  3. June 14th 2012, 03:22 PM #3
    Plato
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    Re: hard definite integral

    Quote Originally Posted by jacks View Post
    \displaystyle \int_{0}^{1}\frac{\sqrt{1-x^2}}{1-x^2\sin^2 x}dx
    ]Use web resources. There is no point in trying this by hand.
    Last edited by Plato; June 14th 2012 at 03:26 PM.
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« Prove this limit | How do I take this definite integral? FRom x^2 to sin(x), of t / t^4 + 1, dt. »

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