$\displaystyle \displaystyle \int_{0}^{1}\frac{\sqrt{1-x^2}}{1-x^2\sin^2 x}dx$

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- Jun 14th 2012, 01:04 AMjackshard definite integral
$\displaystyle \displaystyle \int_{0}^{1}\frac{\sqrt{1-x^2}}{1-x^2\sin^2 x}dx$

- Jun 14th 2012, 03:14 PMsimamuraRe: hard definite integral
This integral can't be found in terms of elementary functions. Use Numerical Integration.

- Jun 14th 2012, 03:22 PMPlatoRe: hard definite integral
**]Use web resources.**There is no point in trying this by hand.