f(x)=(18^x)+(10.5e^x)+(x^20)+(58^21) find f'(x) I understand how to do the last two parts, just not the first two...thanks!
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Originally Posted by ryandman89 f(x)=(18^x)+(10.5e^x)+(x^20)+(58^21) find f'(x) You know that $\displaystyle (e^x)'=e^x$ and $\displaystyle (ae^x)'=ae^x,$ where $\displaystyle a$ is a constant. On the other hand, $\displaystyle 18^x=e^{x\ln18},$ now take its derivative.
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