1) lim ((squ(4+h)-2)/h)((squ(4+h)+2)/(squ(4+h)+2) =
lim (4+h-4)/(h*squ(4+h)+2) =
lim 1/(squ(4+h)+2 =
1/(2+2) =
1/4
2)
0
I don't know if i understood part 2 correctly...
These are the only two i couldn't figure out. If someone could help, that'd be great. Here they are:
1) Limit where h approaches 0- {Square root(4 + h) - 2}/h
In words, the limit where h approaches zero of the square root of four plus h minus 2 all over h.
2) Limit where h approaches 0- 1/{square root(4 + h)} - 1/{2}/h
In words, the limit where h approaches zero of 1 divided by the square root of four plus h minus one half all over h.
Please help, need by tomorrow morning! Thanks!
well, what are your options here? try to simplify the top so that we cancel the h in the bottom, that way we can take the limit. how do we simplify the top? well, we can start by combining the fractions.
well, now what? the h doesn't seem to cancel, so now we apply a common trick, conjugation of the numerator...
now continue and see where you get with this. your answer should be