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Math Help - evaluate limit using squeeze theorem

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    Member sluggerbroth's Avatar
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    evaluate limit using squeeze theorem

    lim f(x) as x goes to 2 where 2x-1 (< or equal) f(x) (< or equal) x^2-2x+3, x does not = 2


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    Re: evaluate limit using squeeze theorem

    Quote Originally Posted by sluggerbroth View Post
    lim f(x) as x goes to 2 where 2x-1 (< or equal) f(x) (< or equal) x^2-2x+3, x does not = 2
    We have 2x-1\leq f(x)\leq x^2-2x+3 for all x\neq2.

    \lim_{x\to2}\left(2x-1\right) = 3 and \lim_{x\to2}\left(x^2-2x+3\right) = 3. So, by the Squeeze Theorem, \lim_{x\to2}f(x)=\mathrm?
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