2x^(7)=1-x (0,1)????
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Originally Posted by sluggerbroth 2x^(7)=1-x (0,1)???? Are you familiar with the Intermediate Value Theorem? We have . Consider the function . We know that and . Since is continuous, what does this tell us?
i'm just learning IVT. not sure what ypu are saying about interval (0,1)
Originally Posted by sluggerbroth i'm just learning IVT. not sure what ypu are saying about interval (0,1) What Reckoner pointed is that there is some "c" where 0 < c < 1 for which f(c) must be 0. In other words there exists atleast one root in (0,1).
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