show solution exists in the interval

2x^(7)=1-x (0,1)????

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Originally Posted by sluggerbroth

2x^(7)=1-x (0,1)????

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Are you familiar with the Intermediate Value Theorem?

We have . Consider the function . We know that and . Since is continuous, what does this tell us?

i'm just learning IVT. not sure what ypu are saying about interval (0,1)

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Originally Posted by sluggerbroth

i'm just learning IVT. not sure what ypu are saying about interval (0,1)

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What Reckoner pointed is that there is some "c" where 0 < c < 1 for which f(c) must be 0. In other words there exists atleast one root in (0,1).