2x^(7)=1-x (0,1)????

Printable View

- Jun 6th 2012, 07:07 PMsluggerbrothshow solution exists in the interval
2x^(7)=1-x (0,1)????

- Jun 6th 2012, 07:35 PMReckonerRe: show solution exists in the interval
Are you familiar with the Intermediate Value Theorem?

We have $\displaystyle 2x^7+x-1=0$. Consider the function $\displaystyle f(x)=2x^7+x-1$. We know that $\displaystyle f(0) = -1$ and $\displaystyle f(1) = 2$. Since $\displaystyle f$ is continuous, what does this tell us? - Jun 6th 2012, 07:53 PMsluggerbrothRe: show solution exists in the interval
i'm just learning IVT. not sure what ypu are saying about interval (0,1)

- Jun 6th 2012, 08:23 PMSarasijRe: show solution exists in the interval