I'm stuck at here...
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Originally Posted by circuscircus Try instead.
What to do next?
Originally Posted by topsquark Try instead.
-Dan Originally Posted by circuscircus
What to do next? Not quite what I was thinking:
And you can proceed from there.
However upon reflection:
is a much simpler method.
You seem to have missed the point of Trig Substitution . . . Let:
Substitute: . . . . . . . . .
Can you finish it now?
Ok gotcha, but I'm confused why (4sec0^2)^2 / (2tan0)^3 is 4... shouldn't it be 4^2 = 16 and 2^3=8, so 16/8 = 2?
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