find an equation for surface of revolution
I have a problem where i need to
find the equation for surface of revolution if the generating curve y = 2x + 1, is revolved about the y axis
The book gives this formula for revolving around the y axis
![x^2 + z^2 = [ r(y)]^2](http://latex.codecogs.com/png.latex?x^2 + z^2 = [ r(y)]^2)
So, wouldnt i just plug y in and square it?
most of the problems have been done this way
Problem is i dont get the right answer.
the answer is

What do i need to do?
Thank you
Re: find an equation for surface of revolution
The equation
is that of a pair of cones (or is it a single cone ?) with a common vertex and an axis of symetry along the
axis. The cones open away from each other from the common vertex. The
in the equation is the radius of the cone and the way that it is written
says that it is a function of
The radius will be zero when
and
when
(or
these coming from the generating line
What you are looking for then is a relationship of the form
for some values of
and
such that
and =0.)
That turns out to be
and when you substitute that into the given equation it simplifies to your given answer.
Re: find an equation for surface of revolution
BobP, mathematically, its a single cone. Each part, that in "standard English" is called a cone, is a "nappe" of that cone.
icelated, the "r(y)" is the function x= f(y) in the plane. Since you are given the line y= 2x+ 1, x= r(y)= (y- 1)/2. That is what should be squared,
so that
.
Re: find an equation for surface of revolution
@HallsofIvy thank you that makes perfect sense.