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- Jun 5th 2012, 01:09 PMCbarker1Rigorous Integration
- Jun 5th 2012, 01:20 PMskeeterRe: Rigorous Integration
integral sqrt((x+1)/(x-2)) dx - Wolfram|Alpha

click on "show steps" ... - Jun 5th 2012, 01:22 PMCbarker1Re: Rigorous Integration
I am confusion how that could be legal in the math world.

- Jun 5th 2012, 01:33 PMPlatoRe: Rigorous Integration
- Jun 5th 2012, 01:42 PMCbarker1Re: Rigorous Integration
I have difficulty written sentences. But i know what i am talking about.

Sorry.

I rewrite that sentence to a questions.

Why the steps in Wolfram Alpha could be correct? If yes, how? - Jun 5th 2012, 06:18 PMHallsofIvyRe: Rigorous Integration
Wolfram Alpha suggests using the substitution precisely what is inside the square root. With that, the integrand becomes just . Now, what about dx?

Well, if then u(x- 1)= ux- u= x+ 1 so ux- x= u+ 1, x(u- 1)= u+1, and . From that, .

Then