Thread: calculus- finding points

Consider the curve given by y^2 = 2 + xy.

It's derivative is y/(2y-x)

Find all points (x,y) on the curve where the line tangent to the curve has slope 1/2.

Thanks

Originally Posted by Mr_Green

Consider the curve given by y^2 = 2 + xy.

It's derivative is y/(2y-x)

Find all points (x,y) on the curve where the line tangent to the curve has slope 1/2.

Thanks

set the derivative = 1/2 and solve for the corresponding x's and y's

.5 = y / (2y-x)

how do i solve for this?

Originally Posted by Mr_Green

.5 = y / (2y-x)

how do i solve for this?

you can begin by multiplying both sides by (2y - x)

Originally Posted by Mr_Green

.5 = y / (2y-x)

how do i solve for this?

So this is true for all points on the curve (0, y) such that .

(You're in Calculus and you can't solve this???)

-Dan