Consider the curve given by y^2 = 2 + xy. It's derivative is y/(2y-x) Find all points (x,y) on the curve where the line tangent to the curve has slope 1/2. Thanks
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Originally Posted by Mr_Green Consider the curve given by y^2 = 2 + xy. It's derivative is y/(2y-x) Find all points (x,y) on the curve where the line tangent to the curve has slope 1/2. Thanks set the derivative = 1/2 and solve for the corresponding x's and y's
.5 = y / (2y-x) how do i solve for this?
Originally Posted by Mr_Green .5 = y / (2y-x) how do i solve for this? you can begin by multiplying both sides by (2y - x)
Originally Posted by Mr_Green .5 = y / (2y-x) how do i solve for this? $\displaystyle \frac{1}{2} = \frac{y}{2y - x}$ $\displaystyle 2y - x = 2y$ $\displaystyle x = 0$ So this is true for all points on the curve (0, y) such that $\displaystyle x \neq 2y$. (You're in Calculus and you can't solve this???) -Dan
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