Solve L'(x)=0 (to two decimal places)
Last edited by PapaJones; May 30th 2012 at 12:01 AM.
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The derivative is not correct.
Derivative of a constant is 0.
You have to solve , this is impossible
It's impossible to solve Or Was the question:
Originally Posted by Siron You have to solve , this is impossible L'(x) = 0 = -64000/x^3 +6
Forgot the 6
Originally Posted by PapaJones L'(x) = 0 = -64000/x^3 +6
Forgot the 6 The derivative of 6 is 0.
Originally Posted by PapaJones if L(x)=32000/x^2+6
Solve L'(x)=0 (to two decimal places) is the original function or ?
... in either case, your derivative is incorrect.
If L(x) =32000/(x^2+6) the derivation is:
L'(x) = - 64000/[(x^2+6)^2]*2x and L'(x) = 0 <=> x = 0
Originally Posted by PapaJones anyhelp please? What kind of "help" do you want? You have simply ignored every post so far.
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