if L(x)=32000/x^2+6

and L'(x)=-64000/x^3+6

Solve L'(x)=0 (to two decimal places)

Results 1 to 11 of 11

- May 29th 2012, 11:12 PM #1

- Joined
- May 2012
- From
- Australia
- Posts
- 6

- May 29th 2012, 11:22 PM #2

- May 29th 2012, 11:41 PM #3

- May 30th 2012, 12:06 AM #4

- Joined
- May 2012
- From
- Australia
- Posts
- 6

- May 30th 2012, 12:47 AM #5

- May 30th 2012, 12:55 AM #6

- May 30th 2012, 12:56 AM #7

- Joined
- May 2012
- From
- Australia
- Posts
- 6

- May 30th 2012, 02:31 AM #8

- May 30th 2012, 04:37 AM #9

- May 30th 2012, 04:46 AM #10

- Joined
- Jan 2011
- Posts
- 9
- Thanks
- 2

- May 30th 2012, 11:08 AM #11

- Joined
- Apr 2005
- Posts
- 15,708
- Thanks
- 1470