Find the derivative: (do not simplify)

f(x) = sec(sqrt(1+(2x/tanx)))

Is this the correct answer?

tan (sqrt(1+(2x/tanx))) sec (sqrt(1+(2x/tanx)))1/2(1+(2x/tanx)))^-1/2 ((2tanx-2xsec^x)/(tan^2x))

sorry I don't know how to make this look any better.

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- May 27th 2012, 10:05 AMtmasChain rule using trig functions
Find the derivative: (do not simplify)

f(x) = sec(sqrt(1+(2x/tanx)))

Is this the correct answer?

tan (sqrt(1+(2x/tanx))) sec (sqrt(1+(2x/tanx)))1/2(1+(2x/tanx)))^-1/2 ((2tanx-2xsec^x)/(tan^2x))

sorry I don't know how to make this look any better. - May 27th 2012, 10:28 AMPlatoRe: Chain rule using trig functions
- May 27th 2012, 10:34 AMtmasRe: Chain rule using trig functions
Why is it x^2 in the second part of the subtraction.. before taking the derivative isn't the numerator:

(2x)'(tanx) - 2x(tanx)' ? I do not quite understand... - May 27th 2012, 10:40 AMPlatoRe: Chain rule using trig functions
That was a typo.

- May 27th 2012, 10:42 AMSorobanRe: Chain rule using trig functions
Hello, tmas!

Quote:

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Correct! . . . Good work!