Find the derivative: (do not simplify)
f(x) = sec(sqrt(1+(2x/tanx)))
Is this the correct answer?
tan (sqrt(1+(2x/tanx))) sec (sqrt(1+(2x/tanx)))1/2(1+(2x/tanx)))^-1/2 ((2tanx-2xsec^x)/(tan^2x))
sorry I don't know how to make this look any better.
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Find the derivative: (do not simplify)
f(x) = sec(sqrt(1+(2x/tanx)))
Is this the correct answer?
tan (sqrt(1+(2x/tanx))) sec (sqrt(1+(2x/tanx)))1/2(1+(2x/tanx)))^-1/2 ((2tanx-2xsec^x)/(tan^2x))
sorry I don't know how to make this look any better.
Almost, The last factor isQuote:
Originally Posted by tmas
Why is it x^2 in the second part of the subtraction.. before taking the derivative isn't the numerator:
(2x)'(tanx) - 2x(tanx)' ? I do not quite understand...
That was a typo.
Hello, tmas!
Quote:
. \;=\;\tan\!\left(\!\sqrt{1+\frac{2x}{\tan x}}}\right)\sec\!\left(\!\sqrt{1+\frac{2x}{\tan x}}\right) \cdot\frac{1}{2}\cdot \left(1+\frac{2x}{\tan x}\right)^{-\frac{1}{2}}\!\left(\frac{2\tan x-2x\sec^2x}{\tan^2x}\right))
Correct! . . . Good work!